Matrix representations
Here we provide the orthogonal form of representing matrices for
the ordinary irreducible matrix representations of symmetric
groups, and also the seminormal form via
as well as three versions of the rational integral form:
The first one is the one described in H. Boerner's book, first
edition, the second one is described in the book by
D. E. Rutherford, in Boerner'st book, second edition, as
well as in the book by G. D. James and A. Kerber.
The third form is due to W. Specht, and it has the advantage
that it allows to evaluate a matrix representation corresponding to
a skew diagram. Here is a little program:
scan(PARTITION,part);
scan(PERMUTATION,perm);
bdg(part,perm,D);
tex(D);
sdg(part,perm,D);
tex(D);
odg(part,perm,D);
tex(D);
specht_dg(part,perm,D);
tex(D);
If you input the partition 2 3 and the permutation (in list
notation) [23451], say then you will receive an output which you
can easily transform in a TeX-readible file of the following form
which shows you the corresponding matrices:
-1 |
-1 |
1 |
1 |
0 |
-1 |
0 |
0 |
0 |
1 |
0 |
-1 |
0 |
0 |
0 |
-1 |
0 |
0 |
1 |
0 |
0 |
-1 |
0 |
1 |
0 |
1 / 4 |
-3 / 8 |
3 / 8 |
-9 / 16 |
0 |
-1 / 2 |
1 / -4 |
-3 / 4 |
3 / -8 |
0 |
-1 / 2 |
-1 / 4 |
1 / 4 |
1 / 8 |
-2 / 3 |
1 |
1 / -6 |
1 / -2 |
1 / 12 |
4 / -9 |
0 |
1 |
0 |
1 / -2 |
1 / -3 |
1 / 4 |
-1 / 4 sqrt( 3 ) |
1 / 4 sqrt( 3 ) |
-3 / 4 |
0 |
-1 / 4 sqrt( 3 ) |
1 / -4 |
-3 / 4 |
1 / -4 sqrt( 3 ) |
0 |
-1 / 4 sqrt( 3 ) |
-1 / 4 |
1 / 4 |
1 / 12 sqrt( 3 ) |
-1 / 3 sqrt( 6 ) |
3 / 4 |
1 / -12 sqrt( 3 ) |
1 / -4 sqrt( 3 ) |
1 / 12 |
1 / -3 sqrt( 2 ) |
0 |
1 / 3 sqrt( 6 ) |
0 |
1 / -3 sqrt( 2 ) |
1 / -3 |
0 |
-1 |
0 |
0 |
0 |
0 |
0 |
-1 |
0 |
0 |
1 |
0 |
-1 |
-1 |
1 |
0 |
0 |
-1 |
0 |
1 |
0 |
1 |
-1 |
-1 |
1 |
For the modular case, SYMMETRICA provides the routines used by
A. Golembiowski which are based on the definition of the
irreducible modules given by M. Clausen using standard
bideterminants. The routine is called
There are also routines for the evaluation of the ordinary
irreducible polynomial representations of general linear groups
GLm(C):
uses symmetry adapted bases in order to decompose the tensor
product ⊗ n(Cm) as
GLm(C)-module. The output is a vector of
polynomial matrices corresponding to the irreducible constituents
(which means the ordinary irreducible polynomial matrix
representations of GL_m associated with the partitions of n with at
most m parts). Here you can use odg (if you call 0L, see the first
line in the following program) or either bdg() (the second line,
calling 1L) for the representations of symmetric groups, and, as
far as it has been tested with bdg(), the polynomials in the
representing matrices turned out to have integral coefficients.
Here is the main part of the program:
scan(INTEGER,m);
scan(INTEGER,n);
glmndg(m,n,M,0L);
println(M);
for(i=0L;i<S_V_LI(M);++i)
glm_homtest(m,S_V_I(M,i));
glmndg(m,n,M,1L);
println(M);
for(i=0L;i<S_V_LI(M);++i)
glm_homtest(m,S_V_I(M,i));
(please note that it contains a test for homomorphism property). In
case you enter 2 for m as well as for n, you will obtain an output
which needs some explanations. Here are the first few lines of the
output:
D = 3 * 1(D1) + 1 * 1(D2)
[
[1
[2:]
:1
[1:1:]
:1
[0:2:]
:]
[2
vdots
The first row of this output indicates that the tensor square
⊗ 2C2 decomposes (as
S2-left module) into three times the representation
D1 of S2 (which corresponds to the first
partition of 2 and therefore is equal to the identity
representation, as we are numbering partitions in the reverse
lexicographical way) and the (alternating) representation
D2 with multiplicity 1. In the second row of the output
we start giving the representing matrix for GL2 row by
row. The first bracket is the bracket of the matrix, the second
bracket indicates that here the first row starts. The first entry 1
is the coefficient of the first monomial in the first entry of the
representing matrix, and so on. The first monomial is indicated by
[2:] which says that only indeterminates of the form
x1,k occur, and just the first one of them, which is
x11, and that its exponent is 2. The end of the first
row is indicated by :]. Hence the upper left hand corner of the
representing matrix is as follows:
(
1⋅
x112 |
1⋅
x11x12 |
1⋅
x122 |
2... |
... |
... |
... |
) |
A more general monomial, say x12x23 is
indicated in this method by
1
[[0:1:0:]
[0:0:1:]:]
Another routine, namely
gives, for a partition of n with at most m parts, the corresponding
irreducible polynomial representation of GLm(C).
It should be noted, that this last routine uses the orthogonal form
of the representations of the symmetric group. Moreover we should
mention that in this case at present no homomorphism test can be
applied. (The homomorphism test, which is the routine
glm_homtest(), as you saw already, runs as follows: Two matrices
are generated, the entries of which are randomly generated integers
between -5 and +5, and it is checked if the product of their images
is the image of their products.)
There is also a way of getting the output in LaTeX-readable form
(but up to now it works only for the representations of general
linear groups). Here is a corresponding test program:
...
glmndg(m,n,M,1L);
println(M);
for(i=0L;i<S_V_LI(M);++i)
latex_glm_dar(S_V_I(M,i));
...
In the case when you enter 2 for m and for n, then the
LaTeX-readable part of the output is, after processing it with
LaTeX:
.
x1 1 x1 2 |
x1 2 x2 1
+x1 1 x2 2 |
x2 1 x2 2 |
|
. |
You see that latex_glm_dar() gives each column of the representing
matrix in a separate array.
harald.fripertinger "at" uni-graz.at, May 26,
2011