Another important fact exhibits a normal subgroup of . In order to show this we introduce the sign as follows:
As implies we have Moreover, the following sets of pairs are equal:
and so we have . Furthermore is a homomorphism of into :
This proves
. Corollary
The sign map
is a homomorphism which is surjective for each .
Hence its kernel
is a normal subgroup of :
The elements of are called even permutations, while the elements of are called odd permutations. Correspondingly, an -cycle is even if and only if is odd. There is a program to compute the sign of various permutations.